document.write( "Question 96962: An automobile race is arranged between two drivers - Steady Eddy - living up to his reputation - manages to average exactly 150 kilometers per hour(kph) for the entire length of the race. Rapid Robert has some mechanical problems early in the race and averages 140 kph for the first half of the length of the race. Rapid Robert recovers during the later stages of the race and averages 160 kph for the second half of the length of the race. What is the outcome of the race? \n" ); document.write( "
Algebra.Com's Answer #70604 by mathslover(157)![]() ![]() You can put this solution on YOUR website! let the total distance by 2d\r \n" ); document.write( "\n" ); document.write( "hence time taken by Eddy 2d/150 \n" ); document.write( " =d/75\r \n" ); document.write( "\n" ); document.write( "Time taken by Robert is d/160 + d/140\r \n" ); document.write( "\n" ); document.write( " = 300d/160*140 \n" ); document.write( " =3d/224\r \n" ); document.write( "\n" ); document.write( "to compare which of the times is larger \n" ); document.write( "we rewrite the fraction d/75 as 3d/225 (multiplying the numerator and denominator by 3)\r \n" ); document.write( "\n" ); document.write( "so time taken by Eddy is 3d/225 \n" ); document.write( "time taken by Robert is 3d/224\r \n" ); document.write( "\n" ); document.write( "clearly \n" ); document.write( "3d/225 < 3d/224 Since denominator is larger in the fraction\r \n" ); document.write( "\n" ); document.write( "Hence Eddy is the winner \n" ); document.write( " |