document.write( "Question 1091602: Use the continuous compound interest formula to find the indicated value.
\n" ); document.write( "A=​94,000​ P=​$81,577​ r=6.3​% t=?
\n" ); document.write( "in years, round 2 places as needed
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Algebra.Com's Answer #706024 by math_helper(2461)\"\" \"About 
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\"+F+=+P+e%5E%28rt%29+\"\r
\n" ); document.write( "\n" ); document.write( "F = Future value (also corresponds to A in this problem)
\n" ); document.write( "P = Present value
\n" ); document.write( "r = annual interest rate, expressed as a decimal
\n" ); document.write( "t = time in years\r
\n" ); document.write( "\n" ); document.write( "—
\n" ); document.write( "Plugging in the given values:
\n" ); document.write( "\"+94000+=+81577e%5E%280.063t%29+\"
\n" ); document.write( "\"+94000%2F81577+=+e%5E%280.063t%29+\"
\n" ); document.write( "\"+ln%2894000%2F81577%29+=+0.063t+\"
\n" ); document.write( "\"+ln%2894000%2F81577%29%2F0.063+=+t+\"
\n" ); document.write( "\"++2.24995+=+t+\"
\n" ); document.write( "—
\n" ); document.write( "Ans: \"+t+=+2.25+\" years
\n" ); document.write( "—
\n" ); document.write( "Check: \"+A+=+81577e%5E%280.063%2A2.25%29+=+94000.24+\" (ok, considering rounding of t to 2.25. More digits of precision must be retained to get the exact answer 94000)
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