document.write( "Question 1091579: The difference between two positive numbers is 18 and 4 times their GM is equal to 5 times their HM find the numbers \n" ); document.write( "
Algebra.Com's Answer #706017 by ikleyn(52790)\"\" \"About 
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document.write( "1)  x - y = 18, with x, y > 0.    (1)\r\n" );
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document.write( "    GM is geometric mean, GM for x, y is defined as \"sqrt%28x+%2A+y%29\".\r\n" );
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document.write( "    HM is harmonic mean, HM for x, y is defined as \"2+%2F+%281%2Fx+%2B+1%2Fy%29\". \r\n" );
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document.write( "2) \"4+%2A+sqrt%28x+%2A+y%29\" = \"5+%2A+%282+%2F+%281%2Fx+%2B+1%2Fy%29%29\" ====>\r\n" );
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document.write( "   \"4%2Asqrt%28xy%29\" = \"10%2F%28%28%28x%2By%29%2Fxy%29%29\"  ====>\r\n" );
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document.write( "   \"4%2Asqrt%28xy%29\" = \"%2810%2Axy%29%2F%28x%2By%29\"  ====>  square both sides  ====>\r\n" );
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document.write( "   \"16%2Axy\" = \"%28100%28xy%29%5E2%29%2F%28x%2By%29%5E2\"  ====>  cancel xy in both sides ====>\r\n" );
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document.write( "   16 = \"%28100xy%29%2F%28x%2By%29%5E2\"  ====> \"16%28x%2By%29%5E2\" = 100xy  ====>  \"4%28x%2By%29%5E2\" = 25xy      (2)\r\n" );
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document.write( "   Now from (1) express  x = y + 18 and substitute it into (2). You will get\r\n" );
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document.write( "   \"4%2A%28%28y%2B18%29%2By%29%5E2\" = 25*(y+18)*y,   or\r\n" );
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document.write( "   \"4%2A%282y%2B18%29%5E2\" = 25*y*(y+18)  ====>  \"16y%5E2+%2B+288y+%2B+1296\" = \"25y%5E2+%2B+450y\" ====>  \"9y%5E2%2B+162y+-+1296\" = 0  ====>  cancel 9 in both sides  ====>\r\n" );
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document.write( "   \"y%5E2+%2B+18y+-+144\" = 0\r\n" );
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document.write( "   (y+24)*(y-6) = 0.\r\n" );
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document.write( "   Since y must be positive, we have only ONE solution for y: y = 6.\r\n" );
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document.write( "   Then  x = y + 18 = 24.\r\n" );
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\n" ); document.write( "\n" ); document.write( "Answer.  x = 24,  y = 6  is the only solution.\r
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\n" ); document.write( "\n" ); document.write( "        The lesson to learn from this solution:\r
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\n" ); document.write( "\n" ); document.write( "        If you choose the correct way, you reduce the problem to the quadratic equation, and there is no need to solve the equation of degree 4.\r
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