document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1091589>Question 1091589</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Carlos has a box of coins that he uses when playing poker with friends. The box currently contains 39 &#8203;coins, consisting of&#8203; pennies, dimes, and quarters. The number of pennies is equal to the number of&#8203; dimes, and the total value is &#8203;$3.90. How many of each denomination of coin does he&#8203; have?<BR>\n" );
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document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #706007 by </B><A HREF=/tutors/aboutme.mpl?userid=jorel1380><B>jorel1380(3719)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=jorel1380><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=jorel1380><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=706007\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Let p be pennies, d be dimes, and q be quarters. The number of pennies is equal to the number of dimes, so p=d. Then:<BR>\n" );
document.write( "p+d+q=39<BR>\n" );
document.write( "2p+q=39 and<BR>\n" );
document.write( "1p+10d+25q=390<BR>\n" );
document.write( "1p+10p+25q=390<BR>\n" );
document.write( "So:<BR>\n" );
document.write( "2p+q=39<BR>\n" );
document.write( "11p+25q=390<BR>\n" );
document.write( "Then solve for p and q. &#9786;&#9786;&#9786;&#9786; </SPAN>\n" );
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