document.write( "Question 96920: Three digit number. The sum of the digits of a three-digit number is 11. If the digits are reversed, the new number is 46 more than five times the old number. If the hundreds digit plus twice the tens digit is equal to the units digit, then what is the number. \n" ); document.write( "

Algebra.Com's Answer #70597 by ankor@dixie-net.com(22740) $\"\"$ $\"About$

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There is simple way to do the problem:
\n" ); document.write( "x = 100's, y = 10's, z = 1,s
\n" ); document.write( ":
\n" ); document.write( "From the phrase \"5 times the old number\" we know that the 1st number x = 1:
\n" ); document.write( "(5 times any other hundreds number would not be 3 digit number)
\n" ); document.write( ":
\n" ); document.write( "\" The sum of the digits of a three-digit number is 11.\" therefore:
\n" ); document.write( "y + z = 10
\n" ); document.write( ":
\n" ); document.write( "\" If the hundreds digit plus twice the tens digit is equal to the units digit,\"
\n" ); document.write( "1 + 2y = z
\n" ); document.write( "y - z = -1
\n" ); document.write( ":
\n" ); document.write( "Add to the 1st equation
\n" ); document.write( "y + z = 10
\n" ); document.write( "2y- z = -1
\n" ); document.write( "----------
\n" ); document.write( "3y = 9
\n" ); document.write( "y = 3
\n" ); document.write( ":
\n" ); document.write( "Obviously z = 7
\n" ); document.write( ":
\n" ); document.write( "then what is the number. 137
\n" ); document.write( "0 solutions \n" ); document.write( "

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