document.write( "Question 1091493: Graph each ellipse and clearly indicate the center, foci, vertices, and co-vertices
\n" ); document.write( "x^2/16 - x/4 + y^2/9 + 4y/9 = 11/16\r
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Algebra.Com's Answer #705896 by MathLover1(20850)\"\" \"About 
You can put this solution on YOUR website!

\n" ); document.write( "\"x%5E2%2F16+-+x%2F4+%2B+y%5E2%2F9+%2B+4y%2F9+=+11%2F16\" ..........complete squares\r
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\n" ); document.write( "\n" ); document.write( "\"%281%2F16%29%28x%5E2+-+4x%29%2B%281%2F9%29%28+y%5E2+%2B+4y%29+=+11%2F16\" \r
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\n" ); document.write( "\n" ); document.write( "\"%281%2F16%29%28x+-+2%29%5E2%2B%281%2F9%29%28+y+%2B+2%29%5E2+=+199%2F144\"\r
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\n" ); document.write( "\n" ); document.write( "\"%289%2F199%29%28x+-+2%29%5E2%2B%2816%2F199%29%28+y+%2B+2%29%5E2+=1\"\r
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\n" ); document.write( "\n" ); document.write( "\"%28x+-+2%29%5E2%2F%28199%2F9%29%2B%28+y+%2B+2%29%5E2%2F%28199%2F16%29+=1\"\r
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\n" ); document.write( "\n" ); document.write( "->\"h=2\" and \"k=-2\", so the center is at (\"2\", \"-2\")\r
\n" ); document.write( "\n" ); document.write( "semi-major axis length: \r
\n" ); document.write( "\n" ); document.write( "\"a=sqrt%28199%2F9%29+=sqrt%28199%29%2F3\"\"a=4.7\"
\n" ); document.write( "semi-minor axis length:\"+b=sqrt%28199%2F16%29+=sqrt%28199%29%2F4\"\"b=3.5\"\r
\n" ); document.write( "\n" ); document.write( "\"c%5E2=a%5E2-b%5E2\"
\n" ); document.write( "\"c%5E2=199%2F9-199%2F16\"
\n" ); document.write( "\"c%5E2=1393%2F144\"
\n" ); document.write( "\"c=sqrt%281393%2F144%29\"
\n" ); document.write( "\"c=sqrt%281393%29%2F12\"\r
\n" ); document.write( "\n" ); document.write( "foci: (\"h+-+c\", \"k\") =(\"2+-+sqrt%281393%29%2F12\", \"-2\") ≈ (\"-1.1\", \"-2\")
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\n" ); document.write( "foci :(\"h+%2Bc\", \"k\") =(\"2+%2Bsqrt%281393%29%2F12\",\"+-2\") ≈ (\"5.1\",\"+-2\")\r
\n" ); document.write( "\n" ); document.write( "vertices:\r
\n" ); document.write( "\n" ); document.write( "The vertices are \"a+=+sqrt%28199%29%2F3\" units above and below the center, at
\n" ); document.write( "(\"2+-+sqrt%28199%29%2F3\", \"-2\") ≈ (\"-2.7\", \"-2\")
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\n" ); document.write( "(\"2+%2B+sqrt%28199%29%2F3\", \"-2\") ≈ (\"6.7\", \"-2\")\r
\n" ); document.write( "\n" ); document.write( "The co-vertices are \"b+=+sqrt%28199%29%2F4\" units to either side of the center, at
\n" ); document.write( "(\"2%2Bsqrt%28199%29%2F4\" , \"-2\") and (\"2-sqrt%28199%29%2F4\", \"-2\")\r
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