document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1091484>Question 1091484</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Find the area of the triangle with the given measurements. Round the solution to the nearest hundredth if necessary. \r<BR>\n" );
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document.write( "A = 48°, b = 30 ft, c = 14 ft\r<BR>\n" );
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document.write( "Show your work please so I can understand.  </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #705890 by </B><A HREF=/tutors/aboutme.mpl?userid=rothauserc><B>rothauserc(4718)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=rothauserc><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=rothauserc><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=705890\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> using the law of cosines<BR>\n" );
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document.write( "A^2 = 30^2 + 14^2 - 30 * 14 * cos(48) = 814.9651<BR>\n" );
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document.write( "A = square root(814.9651) = 28.5476<BR>\n" );
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document.write( "perimeter of triangle(P) = 30 + 14 + 28.5476 = 72.5476<BR>\n" );
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document.write( "using Heron's formula for the area of a triangle<BR>\n" );
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document.write( "s = P/2 = 72.5476 / 2 = 36.2738<BR>\n" );
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document.write( "Area of triangle = square root( 36.2738 * (36.2738 - 30) * (36.2738 - 14) * (36.2738 - 28.5476) ) = 197.8983<BR>\n" );
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document.write( "Area of triangle = 197.90 square feet<BR>\n" );
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