document.write( "Question 1091286: Chebet has y number of goats and x number of sheep.The cost of one goat is 900/= and that of a sheep is 1500/=.In a certain season she made a turnover of 100000/= calculate the number of goats and sheep chebet has \n" ); document.write( "

Algebra.Com's Answer #705883 by greenestamps(13216) $\"\"$ $\"About$

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As the problem is stated, the only way I can make sense out of it is if \"turnover\" is the total cost of the goats and sheep....

\n" ); document.write( "In that case, if x is the number of goats and y is the number of sheep, then we need to find integer solutions to the equation
\n" ); document.write( " $\"900x+%2B+1500y+=+100000\"$

\n" ); document.write( "Unfortunately, there will be no solutions in integers. On the left, both 900 and 1500 are multiples of 3, so the sum 900x + 1500y will be a multiple of 3. But the number on the right is not a multiple of 3.

\n" ); document.write( "If I have interpreted the problem correctly, there is no solution.

\n" ); document.write( "If I have not interpreted the problem correctly, then resubmit the question making it clear what the question is. \n" ); document.write( "

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