document.write( "Question 96964This question is from textbook Introductory Algebra (Blitzer)
\n" ); document.write( ": Things did not go quite as planned. You invested part of $8000 in a stock that paid 12% annual interest. However, the rest of the money suffered a 5% loss. If the total annual income from both investments was $620, how much was invested at each rate? \n" ); document.write( "

Algebra.Com's Answer #70586 by stanbon(75887) $\"\"$ $\"About$

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You invested part of $8000 in a stock that paid 12% annual interest. However, the rest of the money suffered a 5% loss. If the total annual income from both investments was $620, how much was invested at each rate?
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\n" ); document.write( "Let amt invested at 12% be \"x\" ; Interest is 0.12x dollars
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\n" ); document.write( "Amt invested at 5% = \"8000-x\" ; Interest is 0.05(8000-x) = 400-0.05x dollars
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\n" ); document.write( "EQUATION:
\n" ); document.write( "interest + interest = 620 dollars
\n" ); document.write( "0.12x + 400-0.05x = 620
\n" ); document.write( "0.07x = 220
\n" ); document.write( "x = $3142.86 (amt invested at 12%)
\n" ); document.write( "8000-x = $4857.14 ( amt invested at 5%)
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\n" ); document.write( "Cheers,
\n" ); document.write( "Stan H.
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