document.write( "Question 96943: jennifer is one-fourth her father's age. In twelve years, Jennifer will be the same age as her father was 15 years ago. find the present ages of jennifer and her father. \n" ); document.write( "
Algebra.Com's Answer #70568 by mathslover(157)![]() ![]() You can put this solution on YOUR website! Let the present age of Jennifer's father be x \n" ); document.write( "therefore Jennifer's present age = x/4\r \n" ); document.write( "\n" ); document.write( "In twelve years Jennifer's age = x/4 + 12\r \n" ); document.write( "\n" ); document.write( "15 years ago Jeniffer's fathers age was \r \n" ); document.write( "\n" ); document.write( "x-15\r \n" ); document.write( "\n" ); document.write( "Since both these ages are same \n" ); document.write( "=> x/4 + 12 = x-15 \n" ); document.write( "Transpose the similar terms together \n" ); document.write( "x - x/4 = 15 + 12 \n" ); document.write( "3x/4 = 27 \n" ); document.write( "Multiplying by 4/3 on both sides\r \n" ); document.write( "\n" ); document.write( "x= 27* 4/3 =36 \n" ); document.write( "Jeniffer's father's age =36 \n" ); document.write( "Jeniffer's age = 36/4 = 9\r \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " |