document.write( "Question 96943: jennifer is one-fourth her father's age. In twelve years, Jennifer will be the same age as her father was 15 years ago. find the present ages of jennifer and her father. \n" ); document.write( "
Algebra.Com's Answer #70568 by mathslover(157)\"\" \"About 
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Let the present age of Jennifer's father be x
\n" ); document.write( "therefore Jennifer's present age = x/4\r
\n" ); document.write( "\n" ); document.write( "In twelve years Jennifer's age = x/4 + 12\r
\n" ); document.write( "\n" ); document.write( "15 years ago Jeniffer's fathers age was \r
\n" ); document.write( "\n" ); document.write( "x-15\r
\n" ); document.write( "\n" ); document.write( "Since both these ages are same
\n" ); document.write( "=> x/4 + 12 = x-15
\n" ); document.write( "Transpose the similar terms together
\n" ); document.write( "x - x/4 = 15 + 12
\n" ); document.write( "3x/4 = 27
\n" ); document.write( "Multiplying by 4/3 on both sides\r
\n" ); document.write( "\n" ); document.write( "x= 27* 4/3 =36
\n" ); document.write( "Jeniffer's father's age =36
\n" ); document.write( "Jeniffer's age = 36/4 = 9\r
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