document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1091196>Question 1091196</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Assuming that side c is the longest side, what length for side a will produce a right triangle? In triangle ABC, &#61648;A = 60°, and side c = 18 ft. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #705633 by </B><A HREF=/tutors/aboutme.mpl?userid=Alan3354><B>Alan3354(69443)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=Alan3354><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=Alan3354><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=705633\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Assuming that side c is the longest side, what length for side a will produce a right triangle? In triangle ABC, A = 60°, and side c = 18 ft.<BR>\n" );
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document.write( "The 2 sides are:<BR>\n" );
document.write( "18*sin(60)<BR>\n" );
document.write( "18*cos(60)<BR>\n" );
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document.write( "If side a is opposite angle A,<BR>\n" );
document.write( "a = 18*sin(60) = 18*(sqrt(3)/2)<BR>\n" );
document.write( "a = 9*sqrt(3) ft<BR>\n" );
document.write( " </SPAN>\n" );
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