document.write( "Question 96735This question is from textbook geometry
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document.write( ": GIVEN: TRIANGLE ABC IS ISOSCELES; LINE SEGMENT CD IS THE ALTITUDE TO BASE OF LINE SEGMENT AB.\r
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document.write( "PROVE: LINE SEGMENT CD BISECTS ANGLE ACB.\r
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document.write( "I MADE THE PLAN BUT I DON'T THINK IT'S RIGHT BECAUSE I CAN NEVER FINISH THE PROBLEM CORRECTLY.\r
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document.write( "CAN YOU PLEASE PROVIDE ME WITH A PLAN. \n" );
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Algebra.Com's Answer #70562 by mathslover(157)![]() ![]() You can put this solution on YOUR website! Given : triangle ABC is isosceles \n" ); document.write( " CD is the altitude to the base of the triangle \n" ); document.write( "to Prove: Line Segment CD bisects Angle ACB ie angle ACD = angle BCD\r \n" ); document.write( "\n" ); document.write( "Proof: \n" ); document.write( " \n" ); document.write( " In triangles ACD and BCD \n" ); document.write( " AC = BC Sides of an isosceles triangle ABC \n" ); document.write( " CD = CD Common side of the two triangles \n" ); document.write( " angle ADC = BDC =90 given CD is the altitude to the base\r \n" ); document.write( "\n" ); document.write( " therefore triangle ACD is Congruent to triangle BCD ( by the RHS theorem) \n" ); document.write( " \n" ); document.write( " right angle-hypotunese-side \n" ); document.write( " therfore AD=BD \n" ); document.write( " and hence angle ACD = angle BCD angles opposite to the equal sides are also equal \n" ); document.write( " |