document.write( "Question 96735This question is from textbook geometry
\n" ); document.write( ": GIVEN: TRIANGLE ABC IS ISOSCELES; LINE SEGMENT CD IS THE ALTITUDE TO BASE OF LINE SEGMENT AB.\r
\n" ); document.write( "\n" ); document.write( "PROVE: LINE SEGMENT CD BISECTS ANGLE ACB.\r
\n" ); document.write( "\n" ); document.write( "I MADE THE PLAN BUT I DON'T THINK IT'S RIGHT BECAUSE I CAN NEVER FINISH THE PROBLEM CORRECTLY.\r
\n" ); document.write( "\n" ); document.write( "CAN YOU PLEASE PROVIDE ME WITH A PLAN.
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Algebra.Com's Answer #70562 by mathslover(157)\"\" \"About 
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Given : triangle ABC is isosceles
\n" ); document.write( " CD is the altitude to the base of the triangle
\n" ); document.write( "to Prove: Line Segment CD bisects Angle ACB ie angle ACD = angle BCD\r
\n" ); document.write( "\n" ); document.write( "Proof:
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\n" ); document.write( " In triangles ACD and BCD
\n" ); document.write( " AC = BC Sides of an isosceles triangle ABC
\n" ); document.write( " CD = CD Common side of the two triangles
\n" ); document.write( " angle ADC = BDC =90 given CD is the altitude to the base\r
\n" ); document.write( "\n" ); document.write( " therefore triangle ACD is Congruent to triangle BCD ( by the RHS theorem)
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\n" ); document.write( " right angle-hypotunese-side
\n" ); document.write( " therfore AD=BD
\n" ); document.write( " and hence angle ACD = angle BCD angles opposite to the equal sides are also equal
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