document.write( "Question 1091188: solve the following quadratic equation
\n" ); document.write( "x(x-3)(x+3) = 0\r
\n" ); document.write( "\n" ); document.write( "answer is x =0, x=3, x=-3 but I have no idea how to caulculate
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Algebra.Com's Answer #705583 by MathLover1(20849)\"\" \"About 
You can put this solution on YOUR website!
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\n" ); document.write( "\n" ); document.write( "\"x%28x-3%29%28x%2B3%29+=+0\"-> here, you are given zero product (remember zero product theorem, easier way to find zeros) \r
\n" ); document.write( "\n" ); document.write( "so, the product of three numbers \"x\", \"%28x-3%29\", and \"%28x%2B3%29\" will be equal to \"0\" if at least one of them is equal to zero\r
\n" ); document.write( "\n" ); document.write( "it means
\n" ); document.write( "if \"x+=+0\"
\n" ); document.write( "or, if \"%28x-3%29+=+0\"-> this one is equal to zero if \"x=3\"
\n" ); document.write( "or, if \"%28x%2B3%29+=+0\"-> this one is equal to zero if \"x=-3\"\r
\n" ); document.write( "\n" ); document.write( "so, your answer is:\r
\n" ); document.write( "\n" ); document.write( "\"+x+=0\", \"x=3\", \"x=-3\"\r
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