document.write( "Question 1091200: A certain bank pays 12 1/2% (Fraction) per annum simple interest. How much money must a man have in the bank if he will receive $650 interest in 2 years? \n" ); document.write( "
Algebra.Com's Answer #705582 by EMStelley(208)\"\" \"About 
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The formula for simple interest is
\n" ); document.write( "\"A+=+P%281%2Brt%29\"
\n" ); document.write( "where A is the final amount, P is the principal (initial) amount, r is the rate in decimal form, and t is the number of years.
\n" ); document.write( "This question is a little different than the norm, in the sense that we are not giving the principal or final amount, but rather a way to connect the two. We want to have made $650 after 2 years. So if we put P dollars in, we want to receive (P + 650) at the end of 2 years. So for us, A = P + 650. Our rate in decimal form is 0.125 and our t is 2. So let's set that equation up.
\n" ); document.write( "\"P+%2B+650+=+P%281+%2B+0.125%2A2%29\"
\n" ); document.write( "\"P+%2B+650+=+P%281.25%29\"
\n" ); document.write( "Subtracting P from both sides, we get
\n" ); document.write( "\"650+=+0.25P\"
\n" ); document.write( "Thus, P = 2600.
\n" ); document.write( "So if the man wants to make $650 after 2 years, he needs to put $2600 in the bank initially.
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