document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1091100>Question 1091100</A>: <I><SPAN STYLE=\"word-break: break-all;\">  A rectangle has a length of 38 yards less than four times it's width.  The area of the rectangle is 840 yd.² find the length of the rectangle  </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #705554 by </B><A HREF=/tutors/aboutme.mpl?userid=jorel1380><B>jorel1380(3719)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=jorel1380><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=jorel1380><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=705554\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Let w be the width. Then the length would be 4w-38. So:<BR>\n" );
document.write( "w(4w-38)=840<BR>\n" );
document.write( "4w²-38w-840=0<BR>\n" );
document.write( "2w²-19w-420=0<BR>\n" );
document.write( "(2w+21)(w-20)=0<BR>\n" );
document.write( "w=-21/2 or 20<BR>\n" );
document.write( "The width is 20; the length is 42<BR>\n" );
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