document.write( "Question 1091138: please help me solve this \r
\n" ); document.write( "\n" ); document.write( "find the slope and ordinate at the origin of the following equations of straight lines.
\n" ); document.write( "a) y= 3x+2
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Algebra.Com's Answer #705542 by ikleyn(52800) $\"\"$ $\"About$

You can put this solution on YOUR website!
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document.write( "          If the straight line is presented by an equation y = ax + b,\r\n" );
document.write( "          then the slope is equal to \"a\", the coefficient at x.\r\n" );
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\n" ); document.write( "\n" ); document.write( "Now apply this rule to your equations:\r
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document.write( "a)  y = 3x + 2.   The coefficient at \"x\" is 3.  Hence, the slope is 3.\r\n" );
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document.write( "b)  3y = -6x + 3.\r\n" );
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document.write( "    Divide both side by 3. You will get\r\n" );
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document.write( "    y = -2x + 1.  The coefficient at \"x\" is -2.  Hence, the slope is -2.\r\n" );
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\n" ); document.write( "\n" ); document.write( "The lesson to learn and to memorize from this solution:\r
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document.write( "          If the straight line is presented by an equation y = ax + b,\r\n" );
document.write( "          then the slope is equal to \"a\",  the coefficient at x.\r\n" );
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