document.write( "Question 1091071: (X-2),x and (x+2) are three natural numbers.if the product of th three numbers is four times their sum,determine the number \n" ); document.write( "
Algebra.Com's Answer #705489 by ikleyn(52878)\"\" \"About 
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document.write( "The product is x*(x-2)*(x+2) = x*(x^2-4).\r\n" );
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document.write( "The sum is (x-2) + x + (x+2) = 3x.\r\n" );
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document.write( "The equation is \r\n" );
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document.write( "x*(x^2-4) = 3x,\r\n" );
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document.write( "x*(x^2-4) - 3x = 0,\r\n" );
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document.write( "x*(x^2-7) = 0.\r\n" );
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document.write( "It deploys in two independent equations\r\n" );
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document.write( "a) x = 0  with the solution x= 0,   and\r\n" );
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document.write( "b) x^2 - 7 = 0  ====>  x^2 = 7,   which has not integer solutions.\r\n" );
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document.write( "Answer.  The only integer solution is x = 0,  and the integers are -2, 0, and 2.\r\n" );
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