document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1090985>Question 1090985</A>: <I><SPAN STYLE=\"word-break: break-all;\"> solve for x in 2^(2x+1)-1/8=1/32 </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #705437 by </B><A HREF=/tutors/aboutme.mpl?userid=Alan3354><B>Alan3354(69443)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=Alan3354><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=Alan3354><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=705437\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> solve for x in 2^(2x+1)-1/8=1/32<BR>\n" );
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document.write( "2^(2x+1)-1/8=1/32<BR>\n" );
document.write( "2^(2x+1) = 1/32 + 1/8 = 5/32<BR>\n" );
document.write( "32*2^(2x+1) = 5<BR>\n" );
document.write( "2^5*2^(2x+1) = 5<BR>\n" );
document.write( "2^(2x+6) = 5\r<BR>\n" );
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document.write( "(2x+6)*log(2) = log(5)<BR>\n" );
document.write( "2x+6 = log(5)/log(2)<BR>\n" );
document.write( "2x = -6 + log(5)/log(2)<BR>\n" );
document.write( "x = -3 + ((log(5)/log(2))/2<BR>\n" );
document.write( "x =~ -1.839\r<BR>\n" );
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document.write( " </SPAN>\n" );
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