document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1090993>Question 1090993</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Find the simple interest on 500 borrowed for 3 years at 8% per annum.\r<BR>\n" );
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document.write( "How do you do it? <BR>\n" );
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document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #705435 by </B><A HREF=/tutors/aboutme.mpl?userid=Theo><B>Theo(13342)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=Theo><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=Theo><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=705435\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> simple interest formula is i = p * r * n\r<BR>\n" );
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document.write( "i is the interest<BR>\n" );
document.write( "p is the principal<BR>\n" );
document.write( "r is the interest rate per time period<BR>\n" );
document.write( "n is the number of time periods\r<BR>\n" );
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document.write( "your time period is in years.\r<BR>\n" );
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document.write( "r = .08 per year<BR>\n" );
document.write( "n = 3 years.<BR>\n" );
document.write( "p = 500\r<BR>\n" );
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document.write( "formula of i = p * r * n becomes i = 500 * .08 * 3 which results in i = 120.\r<BR>\n" );
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