document.write( "Question 1090992: The expression 2n+1 represents an odd integer. Write an expression to find three consecutive odd integers whose sum is 63.\r
\n" ); document.write( "\n" ); document.write( "I know the answer to be 19, 21, and 23. If I use n+n+2+n+4=63. I can't make the 2n+1 work.
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Algebra.Com's Answer #705431 by Theo(13342)\"\" \"About 
You can put this solution on YOUR website!
n represents any integer as far as i know.\r
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\n" ); document.write( "\n" ); document.write( "the odd number is represented by 2n + 1\r
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\n" ); document.write( "\n" ); document.write( "that would be the first number.\r
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\n" ); document.write( "\n" ); document.write( "the second odd number would be 2n + 3\r
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\n" ); document.write( "\n" ); document.write( "the third odd number would be 2n + 5\r
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\n" ); document.write( "\n" ); document.write( "you get 2n + 1 + 2n + 3 + 2n + 5 = 63\r
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\n" ); document.write( "\n" ); document.write( "combine like terms to get 6n + 9 = 63\r
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\n" ); document.write( "\n" ); document.write( "subtract 9 from both sides to get 6n = 54\r
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\n" ); document.write( "\n" ); document.write( "divide both sides by 6 to get n = 9\r
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\n" ); document.write( "\n" ); document.write( "when n = 9:\r
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\n" ); document.write( "\n" ); document.write( "2n + 1 = 19\r
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\n" ); document.write( "\n" ); document.write( "2n + 3 = 21\r
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\n" ); document.write( "\n" ); document.write( "2n + 5 = 23\r
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