document.write( "Question 96891: Part of $5000 is invested at 4% and the rest at 5%. The annual interest on the 5% was $124.00 more than the interest on the 4% investment. How much was invested at each rate?\r
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Algebra.Com's Answer #70542 by scott8148(6628)\"\" \"About 
You can put this solution on YOUR website!
x(4%)+(5000-x)(5%)=x(4%)+(x(4%)+124)\r
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\n" ); document.write( "\n" ); document.write( ".04x+250-.05x=.08x+124 ... 126=.09x ... 1400=x ... 3600=5000-x
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