document.write( "Question 1090936: find the limit:
\n" ); document.write( "lim x approaches 3, 3 sqrt 2x^2 -10 \r
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Algebra.Com's Answer #705377 by ikleyn(52800)\"\" \"About 
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\n" ); document.write( "find the limit:
\n" ); document.write( "lim x approaches 3, \"highlight%283%2Asqrt%282x%5E2-10%29%29\" \r
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\n" ); document.write( "~~~~~~~~~~~~~~~~~\r
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\n" ); document.write( "\n" ); document.write( "Notice how I edited your input using parentheses 3*sqrt(2x^2-10) to make your formula readable . . . \r
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document.write( "1.  The number 3 together with its neighborhood lies in the domain of the given function.\r\n" );
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document.write( "2.  In addition, the function  \"3%2Asqrt%282x%5E2-10%29\" is continuous at the poin x= 3.\r\n" );
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document.write( "3.  Therefore, you can simply substitute the value x= 3 into the function to get its limit as x approaches 3:\r\n" );
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document.write( "    lim  \"3%2Asqrt%282x%5E2-10%29\" = \"3%2Asqrt%282%2A3%5E2-10%29\" = \"3%2Asqrt%282%2A9-10%29\" = \"3%2Asqrt%288%29\" = \"6%2Asqrt%282%29\".\r\n" );
document.write( "   x-->3\r\n" );
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\n" ); document.write( "\n" ); document.write( "Solved.\r
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