document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1090921>Question 1090921</A>: <I><SPAN STYLE=\"word-break: break-all;\"> How to solve this?<BR>\n" );
document.write( "x+3y-5z=-29<BR>\n" );
document.write( "3y+2z=18<BR>\n" );
document.write( "y=-5x-23 </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #705360 by </B><A HREF=/tutors/aboutme.mpl?userid=Alan3354><B>Alan3354(69443)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=Alan3354><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=Alan3354><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=705360\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> How to solve this?<BR>\n" );
document.write( "x+3y-5z=-29<BR>\n" );
document.write( "3y+2z=18<BR>\n" );
document.write( "y=-5x-23<BR>\n" );
document.write( "===========<BR>\n" );
document.write( "Since y is defined in Eqn 3, sub for y in the other 2.<BR>\n" );
document.write( "Subbing for y in the 2nd eqn gives an eqn in x.<BR>\n" );
document.write( "solve for x.<BR>\n" );
document.write( "----\r<BR>\n" );
document.write( "\n" );
document.write( " </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );