document.write( "Question 1090862: A special rubber ball is dropped from the top of a building 81m high. if after the falling it bounces back to two-thirds of the previous bouncing height, then
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Algebra.Com's Answer #705350 by Alan3354(69443)\"\" \"About 
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A special rubber ball is dropped from the top of a building 81m high. if after the falling it bounces back to two-thirds of the previous bouncing height, then
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\n" ); document.write( "81 m *(2/3)^5 = 81*32/243 = 32/3 meters
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\n" ); document.write( "what is the total distance it has covered the 6th time it touch the ground?
\n" ); document.write( "Find the height of each bounce.
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\n" ); document.write( "0th - 81 meters (when released)
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\n" ); document.write( "1st - 81*2/3 = 54 up, 54 down
\n" ); document.write( "2nd - 54*2/3 = 36
\n" ); document.write( "3rd - 36*2/3 = 24
\n" ); document.write( "4th - 24*2/3 = 16
\n" ); document.write( "5th - 16*2/3 = 32/3
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\n" ); document.write( "Add 1st thru 5th = 422/3 meters up and down
\n" ); document.write( "Times 2 = 844/3 meters traveled.
\n" ); document.write( "+ the 81 meter drop --> 1087/3 meters
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