document.write( "Question 96906: At 9am a truck leaves the truck yard and travels west at a rate of 45 mi/hr. Two hours later, a second truck leaves along the same route, traveling at 75 mi./hr/ When will the second truck catch up to the first? \n" ); document.write( "
Algebra.Com's Answer #70532 by stanbon(75887)\"\" \"About 
You can put this solution on YOUR website!
At 9am a truck leaves the truck yard and travels west at a rate of 45 mi/hr. Two hours later, a second truck leaves along the same route, traveling at 75 mi./hr/ When will the second truck catch up to the first?
\n" ); document.write( "-----------
\n" ); document.write( "1st truck DATA:
\n" ); document.write( "Rate = 45 mph ; time = x hrs ; distance = 45x miles
\n" ); document.write( "--------------------
\n" ); document.write( "2nd truck DATA:
\n" ); document.write( "Rate = 75 mph ; time = x-2 hrs ; distance = 75(x-2) = 75x-150 miles
\n" ); document.write( "--------------------
\n" ); document.write( "EQUTION:
\n" ); document.write( "distance = distance
\n" ); document.write( "45x = 75x-150
\n" ); document.write( "30x = 150
\n" ); document.write( "x = 5 hrs
\n" ); document.write( "----------------
\n" ); document.write( "2nd truck will catch 1st 5 hrs after 9:00AM or at 2:00PM
\n" ); document.write( "=============
\n" ); document.write( "Cheers,
\n" ); document.write( "Stan H. \n" ); document.write( "
\n" );