document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1090804>Question 1090804</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Ok so I have another question - I'm struggling to get log laws and have the question, I appreciate getting the answer but really need to understand what's happening that I'm not grasping<BR>\n" );
document.write( "Express y in terms of x<BR>\n" );
document.write( "x=4(3^y) + 3^y - 3(^y+log_3x)<BR>\n" );
document.write( "So my thought was to take 4 over to the left so it becomes<BR>\n" );
document.write( "x/4 = 3^y + 3^y - 3(^y+log_3x)<BR>\n" );
document.write( "Then to get the powers down, use natural log and multiply out brackets<BR>\n" );
document.write( "ln(x/4)= yln3 + yln3 - yln3 - log_3xln3<BR>\n" );
document.write( "I would think then that yln3 - yln3 would cancel each other out, so<BR>\n" );
document.write( "ln(x/4) = yln3 - log_3xln3<BR>\n" );
document.write( "This is where my thought process gets stuck as I know log_3 3 is 1 but not sure about what log_3xln3 is telling me<BR>\n" );
document.write( "my final answer would be ((x/4)+x)/ln3 = y<BR>\n" );
document.write( " </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #705261 by </B><A HREF=/tutors/aboutme.mpl?userid=ankor@dixie-net.com><B>ankor@dixie-net.com(22740)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=ankor@dixie-net.com><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=ankor@dixie-net.com><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=705261\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> I am not sure what the \"^\" means in the expression: 3(^y+log_3x)<BR>\n" );
document.write( "Is it <IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=3%5E%28%28y%2Blog%283x%29%29%29 ALIGN=MIDDLE  ALT=\"3%5E%28%28y%2Blog%283x%29%29%29\"   DISABLED_style= \"max-width:90%; height:auto;\" > or what?<BR>\n" );
document.write( "So we have<BR>\n" );
document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=x=4%283%5Ey%29+%2B+3%5Ey+-+3%5E%28y%2Blog%283x%29%29 ALIGN=MIDDLE  ALT=\"x=4%283%5Ey%29+%2B+3%5Ey+-+3%5E%28y%2Blog%283x%29%29\"   DISABLED_style= \"max-width:90%; height:auto;\" ><BR>\n" );
document.write( "if you divide by 4 here you have to divide each term by 4, not like you did it.<BR>\n" );
document.write( "3^y are like terms so you can add them<BR>\n" );
document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=x=5%283%5Ey%29-+3%5E%28y%2Blog%283x%29%29 ALIGN=MIDDLE  ALT=\"x=5%283%5Ey%29-+3%5E%28y%2Blog%283x%29%29\"   DISABLED_style= \"max-width:90%; height:auto;\" ><BR>\n" );
document.write( "we can rearrange it<BR>\n" );
document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=5%283%5Ey%29=+x+%2B+3%5E%28y%2Blog%283x%29%29 ALIGN=MIDDLE  ALT=\"5%283%5Ey%29=+x+%2B+3%5E%28y%2Blog%283x%29%29\"   DISABLED_style= \"max-width:90%; height:auto;\" ><BR>\n" );
document.write( "divide both sides by 5<BR>\n" );
document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=3%5Ey+=+%28x+%2B+3%5E%28y%2Blog%283x%29%29%29%2F5 ALIGN=MIDDLE  ALT=\"3%5Ey+=+%28x+%2B+3%5E%28y%2Blog%283x%29%29%29%2F5\"   DISABLED_style= \"max-width:90%; height:auto;\" ><BR>\n" );
document.write( "this is as far as I have time for right now, will continue this later\r<BR>\n" );
document.write( "<BR>\n" );
document.write( "\n" );
document.write( " </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );