document.write( "Question 1090788: 8 gallons of a 55% acid solution was mixed with 12 gallons of a 65% acid solution. Find the concentration of the new mixture. i really need help with this question. thanks :) \n" ); document.write( "
Algebra.Com's Answer #705238 by ikleyn(52797)\"\" \"About 
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document.write( "8  gallons of 55% acid solution contain 0.55*8 gallons of the pure acid.\r\n" );
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document.write( "12 gallons of 65% acid solution contain 0.65*12 gallons of the pure acid.\r\n" );
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document.write( "The mixture contains  0.55*8 + 0.65*12  gallons of the pure acid and has the volume of 8 + 12 = 20 gallons.\r\n" );
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document.write( "Therefore, the concentration under the question is  \"%28%280.55%2A8+%2B+0.65%2A12%29%2F%288%2B20%29%29%2A100\" percents.\r\n" );
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document.write( "          Notice that I multiplied by 100 to get the percentage instead of fraction.\r\n" );
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document.write( "You complete all necessary calculations.\r\n" );
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