document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1090673>Question 1090673</A>: <I><SPAN STYLE=\"word-break: break-all;\"> A group of friends go out to dinner one evening. They agree to share the R1 120 bill evenly. However, three members forget their wallets and cannot pay. The remaining friends have to pay an extra R84 to settle the bill. How many friends are in the group?  </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #705209 by </B><A HREF=/tutors/aboutme.mpl?userid=jorel1380><B>jorel1380(3719)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=jorel1380><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=jorel1380><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=705209\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Let n be the number of friends with wallets. Then, the total number of diners would be n+3. So:<BR>\n" );
document.write( "1120/(n+3) +84=1120/n<BR>\n" );
document.write( "1120n+84(nē+3n)=1120(n+3)<BR>\n" );
document.write( "84nē+252n-3360=0<BR>\n" );
document.write( "nē+3n-40=0<BR>\n" );
document.write( "(n+8)(n-5)=0<BR>\n" );
document.write( "n=5 or -8<BR>\n" );
document.write( "n=5<BR>\n" );
document.write( "n+3=8<BR>\n" );
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