document.write( "Question 1090712: Find the nth term of the series 3 7 14 27 52 \n" ); document.write( "
Algebra.Com's Answer #705188 by Edwin McCravy(20056)\"\" \"About 
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document.write( "3 7 14 27 52\r\n" );
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document.write( "Subtract the integers starting with 0, which has nth term n-1\r\n" );
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document.write( "0 1  2  3  4\r\n" );
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document.write( "That gives:\r\n" );
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document.write( "3 6 12 24 48     \r\n" );
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document.write( "That's a geometric series with nth term 3∙2n-1\r\n" );
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document.write( "So the general term is\r\n" );
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document.write( "3∙2n-1 + n - 1\r\n" );
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document.write( "Checking by substituting n=1...5\r\n" );
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document.write( "3∙21-1 + 1 - 1 = 3∙20+0 = 3∙1 = 3\r\n" );
document.write( "3∙22-1 + 2 - 1 = 3∙21+1 = 3∙2+1 = 6+1 = 7\r\n" );
document.write( "3∙23-1 + 3 - 1 = 3∙22+2 = 3∙4+2 = 12+2 = 14\r\n" );
document.write( "3∙24-1 + 4 - 1 = 3∙23+3 = 3∙8+3 = 24+3 = 27\r\n" );
document.write( "3∙25-1 + 5 - 1 = 3∙23+1 = 3∙16+4 = 48+5 = 52\r\n" );
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document.write( "It checks.\r\n" );
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document.write( "Edwin
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