document.write( "Question 1090675: hi can someone please help? thanks
\n" ); document.write( "A 300 g sample of thorium-234 has a half-life of 24 days. The mass of thorium, in grams, that remains after t days can be modelled by m(t)=300(1/2)^t/24 . What mass will remain after 31 days?
\n" ); document.write( "a. 122.5 g
\n" ); document.write( "b. 150 g
\n" ); document.write( "c. 177.5 g
\n" ); document.write( "d. 193.75 g
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Algebra.Com's Answer #705140 by jim_thompson5910(35256)\"\" \"About 
You can put this solution on YOUR website!

\n" ); document.write( "Plug in t = 31 and use a calculator to evaluate.\r
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\n" ); document.write( "\n" ); document.write( "m(t)=300(1/2)^(t/24)
\n" ); document.write( "m(31)=300(1/2)^(31/24)
\n" ); document.write( "m(31)=122.543658993082
\n" ); document.write( "m(31)=122.5\r
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\n" ); document.write( "\n" ); document.write( "You'll have 122.5 grams of thorium left over after 31 days.
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