document.write( "Question 96880: I'm stumped. I tried multiplying by 3 to isolate the 2x, and tried combining fractions then dividing, but none of my attempts have been right. Can anyone help please?\r
\n" ); document.write( "\n" ); document.write( "Solve the inequality. Write the solution set in interval notation.
\n" ); document.write( "-2/3 >= 2x/3 - 3/4
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\n" ); document.write( "\n" ); document.write( " \n" ); document.write( "
Algebra.Com's Answer #70513 by coyote(32)\"\" \"About 
You can put this solution on YOUR website!
-2/3 >= 2x/3 - 3/4
\n" ); document.write( "Multiply thru by 12 to get rid of the denominators:
\n" ); document.write( "-8 >= 8x -9
\n" ); document.write( "1 <= 8x
\n" ); document.write( "x >= 1/8
\n" ); document.write( "-----------
\n" ); document.write( "Interval notation: [1/8,inf)\r
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\n" ); document.write( "\n" ); document.write( "Almost, but you helped immensely when I realized the one >= was just reversed!
\n" ); document.write( "Thank you!
\n" ); document.write( "-2/3 >= 2x/3 - 3/4
\n" ); document.write( "Multiply thru by 12 to get rid of the denominators:
\n" ); document.write( "-8 >= 8x -9
\n" ); document.write( "1 >= 8x
\n" ); document.write( "x <= 1/8
\n" ); document.write( "-----------
\n" ); document.write( "Interval notation: [inf,1/8)
\n" ); document.write( " \n" ); document.write( "
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