document.write( "Question 1090653: Two fuel mixtures, one of 2.0% oil and 98% gasoline and another of 8.0% oil and 92% gasoline are to be mixed to make 10L of a fuel that is 4.0% oil and 96% gasoline that is to be used in a chain saw. How much of each L mixture is needed? I need to know the process of algebra that is used to calculate the answer. \n" ); document.write( "
Algebra.Com's Answer #705114 by josgarithmetic(39620)![]() ![]() ![]() You can put this solution on YOUR website! 4% oil is \n" ); document.write( "\n" ); document.write( "-\r \n" ); document.write( "\n" ); document.write( "x, how much of the 2% oil \n" ); document.write( "10-x, how much of the 8% oil\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( " \n" ); document.write( "\n" ); document.write( " \n" ); document.write( "\n" ); document.write( " \n" ); document.write( "\n" ); document.write( " \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " |