document.write( "Question 1090653: Two fuel mixtures, one of 2.0% oil and 98% gasoline and another of 8.0% oil and 92% gasoline are to be mixed to make 10L of a fuel that is 4.0% oil and 96% gasoline that is to be used in a chain saw. How much of each L mixture is needed? I need to know the process of algebra that is used to calculate the answer. \n" ); document.write( "
Algebra.Com's Answer #705114 by josgarithmetic(39620)\"\" \"About 
You can put this solution on YOUR website!
4% oil is \"1%2F3\" of the way from 2% oil to 8% oil. Does this help you?\r
\n" ); document.write( "\n" ); document.write( "-\r
\n" ); document.write( "\n" ); document.write( "x, how much of the 2% oil
\n" ); document.write( "10-x, how much of the 8% oil\r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "\"2x%2B8%2810-x%29=4%2A10\"\r
\n" ); document.write( "\n" ); document.write( "\"x%2B4%2810-x%29=20\"\r
\n" ); document.write( "\n" ); document.write( "\"x%2B40-4x=20\"\r
\n" ); document.write( "\n" ); document.write( "\"-3x=-20\"\r
\n" ); document.write( "\n" ); document.write( "\"x=20%2F3\"\r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "\"x=6%262%2F3\", Liters of the 2% oil mixture
\n" ); document.write( "\"3%261%2F3\", Liters of the 8% oil mixture
\n" ); document.write( "
\n" );