document.write( "Question 1090612: Let f(x) be a rational function such that when f(x) is in reduced form, the numerator and denominator both have degree 3. What sorts of asymptotes could f(x) have?
\n" ); document.write( "a. Three vertical asymptotes only
\n" ); document.write( "b. One vertical asymptote and one oblique asymptote
\n" ); document.write( "c. One horizontal asymptote and at least one vertical asymptote
\n" ); document.write( "d. One horizontal and one oblique asymptote
\n" ); document.write( "e. No vertical asymptotes and no horizontal asymptotes
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Algebra.Com's Answer #705105 by MathLover1(20850)\"\" \"About 
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\n" ); document.write( "The graph of f(x) will have vertical asymptotes at those values of \"x\" for which the \"denominator\" is equal to zero.=> \"denominator\" could be equal to zero for \"one\",\"two\", or \"three\" values of \"x\"\r
\n" ); document.write( "\n" ); document.write( " If \"m=n\" (that is, the degrees of the numerator and denominator are the same), then the graph of \"f%28x%29\" will have \"one\" horizontal asymptote at \"y=a%5Bn%5D%2Fb%5Bm%5D\". (coefficients of highest degree)\r
\n" ); document.write( "\n" ); document.write( "When the degree of the numerator is exactly \"one\" more than the degree of the denominator, the graph of the rational function will have an oblique asymptote.\r
\n" ); document.write( "\n" ); document.write( "in your case, the degree of the numerator and denominator are same; so, there is no oblique asymptote \r
\n" ); document.write( "\n" ); document.write( "so, your answer is:\r
\n" ); document.write( "\n" ); document.write( "c. One horizontal asymptote and at least one vertical asymptote\r
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