document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=14010>Question 14010</A>: <I><SPAN STYLE=\"word-break: break-all;\"> 4/x-1=3 </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #7051 by </B><A HREF=/tutors/aboutme.mpl?userid=LilSkittleMd><B>LilSkittleMd(119)</B></A><img src=\"/images/stars/stars-09.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=LilSkittleMd><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=7051\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> First you need to find the least common denominator, which is x-1. Multiply both sides of the equation by x-1. This will cancel out the x-1 on one side, leaving only 4. Then solve.<BR>\n" );
document.write( "4/x-1=3<BR>\n" );
document.write( "[4/x-1](x-1)=3(x-1)<BR>\n" );
document.write( "The two x-1's cancel out<BR>\n" );
document.write( "4=3x-3<BR>\n" );
document.write( "7=3x<BR>\n" );
document.write( "(7/3)=x </SPAN>\n" );
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