document.write( "Question 1090623: A plane flew from Minneapolis to Atlanta, a distance of 900 miles, against a 30 mph-headwind. On the return
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document.write( "flight, the 30-mph wind became a tailwind. The plane was in the air for a total of 5 ½ hours. What would
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document.write( "the plane’s average speed have been without the wind?� \n" );
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Algebra.Com's Answer #705079 by jorel1380(3719)![]() ![]() You can put this solution on YOUR website! Let s be the speed of the plane in still air. Then: \n" ); document.write( "900/s+30 + 900/s-30=5.5 \n" ); document.write( "900(s-30)+900(s+30)=5.5(s²-900) \n" ); document.write( "1800s=5.5s²-4950 \n" ); document.write( "5.5s²-1800s-4950=0 \n" ); document.write( "11s²-3600s-9900=0 \n" ); document.write( "(11s+30)(s-330)=0 \n" ); document.write( "s=-30/11 or 330 \n" ); document.write( "We get a positive value of 330 for the speed of the plane in still air \n" ); document.write( "☺☺☺☺ \n" ); document.write( " |