document.write( "Question 1090577: A triangle field ABC is such that AB=90 m, BC=70 m & AC=85 m. Make a scale drawing of it, using a scale of 1 cm to 10 m. From your scale drawing, find
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document.write( "(a) the actual distance from A to the midpoint of BC and,
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document.write( "(b) the actual distance from B to the midpoint of AC. \n" );
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Algebra.Com's Answer #705072 by Fombitz(32388) You can put this solution on YOUR website! \n" ); document.write( "Not sure how you get actual distances from a scale drawing. \n" ); document.write( "You can get an estimate of the distances. \n" ); document.write( ". \n" ); document.write( ". \n" ); document.write( ". \n" ); document.write( "I'm solving it algebraically. \n" ); document.write( ". \n" ); document.write( ". \n" ); document.write( ". \n" ); document.write( "So let's set up a coordinate system with (0,0) at A. \n" ); document.write( "So then B is (90,0). \n" ); document.write( "Angle A is 47.1. \n" ); document.write( "Angle B is 62.7. \n" ); document.write( "Angle C is 70.2. \n" ); document.write( "So then the coordinates of C is \n" ); document.write( "C:( \n" ); document.write( "C:( \n" ); document.write( "The midpoint of AC would then be half of those values. \n" ); document.write( " \n" ); document.write( "So then using the distance formula. \n" ); document.write( " \n" ); document.write( "Solve for \n" ); document.write( ". \n" ); document.write( ". \n" ); document.write( ". \n" ); document.write( "The midpoint of BC is calculated using the points B and C. \n" ); document.write( "It's the average of the x and y values. \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "Again use the distance formula, \n" ); document.write( " \n" ); document.write( "Solve for |