document.write( "Question 1090581: Two numbers (x & y) differ by 4, but their product is 96. What are the two numbers?
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document.write( "I tried:
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document.write( "x(y+4)=96
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document.write( "xy+4x-96=0
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document.write( "(x+12)(y-8)
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document.write( "x=-12 y=8\r
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document.write( "It's not an age question but I thought it might be able to be done in a similar way.
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document.write( "
Algebra.Com's Answer #705031 by Edwin McCravy(20055)![]() ![]() You can put this solution on YOUR website! \n" ); document.write( "Two numbers (x & y) differ by 4, \n" ); document.write( " \r\n" ); document.write( "x-y = 4 <--first equation\r\n" ); document.write( " \n" ); document.write( "but their product is 96. \n" ); document.write( " \r\n" ); document.write( "xy = 96 <--second equation\r\n" ); document.write( "\r\n" ); document.write( "Solve the first equation for x\r\n" ); document.write( "\r\n" ); document.write( "x = y+4\r\n" ); document.write( "\r\n" ); document.write( "Substitute in the second equation:\r\n" ); document.write( "\r\n" ); document.write( "(y+4)y = 96\r\n" ); document.write( "\r\n" ); document.write( "y(y+4) = 96\r\n" ); document.write( "\r\n" ); document.write( "y²+4y-96 = 0\r\n" ); document.write( "\r\n" ); document.write( "(y+12)(y-8) = 0\r\n" ); document.write( "\r\n" ); document.write( "y+12=0; y-8=0\r\n" ); document.write( " y=-12 y=8\r\n" ); document.write( "\r\n" ); document.write( "if y = -12, we substitute in\r\n" ); document.write( "\r\n" ); document.write( "x = y+4 \r\n" ); document.write( "x = -12+4\r\n" ); document.write( "x = -8\r\n" ); document.write( "\r\n" ); document.write( "So one answer is x = -8 and y = -12\r\n" ); document.write( "\r\n" ); document.write( "if y = 8, we substitute in\r\n" ); document.write( "\r\n" ); document.write( "x = y+4 \r\n" ); document.write( "x = 8+4\r\n" ); document.write( "x = 12\r\n" ); document.write( "\r\n" ); document.write( "So the other answer is x = 12 and y = 8\r\n" ); document.write( "\r\n" ); document.write( "Edwin\n" ); document.write( " |