document.write( "Question 1090549: Find three consecutive integers such that the sum of the largest and four times the second is 42 more than the first. \n" ); document.write( "
Algebra.Com's Answer #705025 by richwmiller(17219)\"\" \"About 
You can put this solution on YOUR website!
a,a+1,a+2\r
\n" ); document.write( "\n" ); document.write( "a+2+(4*(a+1))=a+42
\n" ); document.write( "a+2+4a+4=a+42
\n" ); document.write( "5a+6=a+42
\n" ); document.write( "4a=36
\n" ); document.write( "a=9
\n" ); document.write( "a+1=10
\n" ); document.write( "a+2=11
\n" ); document.write( "check
\n" ); document.write( "11+4*10=42+9
\n" ); document.write( "51=51
\n" ); document.write( "ok\r
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