document.write( "Question 1090549: Find three consecutive integers such that the sum of the largest and four times the second is 42 more than the first. \n" ); document.write( "
Algebra.Com's Answer #705025 by richwmiller(17219)![]() ![]() You can put this solution on YOUR website! a,a+1,a+2\r \n" ); document.write( "\n" ); document.write( "a+2+(4*(a+1))=a+42 \n" ); document.write( "a+2+4a+4=a+42 \n" ); document.write( "5a+6=a+42 \n" ); document.write( "4a=36 \n" ); document.write( "a=9 \n" ); document.write( "a+1=10 \n" ); document.write( "a+2=11 \n" ); document.write( "check \n" ); document.write( "11+4*10=42+9 \n" ); document.write( "51=51 \n" ); document.write( "ok\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " |