document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1090515>Question 1090515</A>: <I><SPAN STYLE=\"word-break: break-all;\"> A man has rs 35000 invested part 3 and half percent and the rest at 4% the total income is Rs 1300 find the sum invested at each rate<BR>\n" );
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document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #704972 by </B><A HREF=/tutors/aboutme.mpl?userid=jorel1380><B>jorel1380(3719)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=jorel1380><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=jorel1380><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=704972\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Let n be the amount invested at 4%. Then, the amount invested at 3.5% would be 35000-n. So:<BR>\n" );
document.write( ".04n+.035(35000-n)=1300<BR>\n" );
document.write( "Then, solve for n.<BR>\n" );
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