document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1090497>Question 1090497</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Express in expanded form if possible.  Thanks for helping.\r<BR>\n" );
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document.write( "(<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=+log+b ALIGN=MIDDLE  ALT=\"+log+b\"   DISABLED_style= \"max-width:90%; height:auto;\" > x^3) * sqrt(y) </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #704964 by </B><A HREF=/tutors/aboutme.mpl?userid=Boreal><B>Boreal(15235)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=Boreal><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=Boreal><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=704964\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> The first is 3 log b(x) and the second is (1/2) log b (y)<BR>\n" );
document.write( "These are combined and added to get 3 log b (x)+(1/2) log b (y)<BR>\n" );
document.write( "Check using b=2 x=4 and y=32<BR>\n" );
document.write( "3log 2 (4)+(1/2)log2 32<BR>\n" );
document.write( "6 plus (1/2)*5=8.5<BR>\n" );
document.write( "log 2(64*sqrt(32)=log 2(64*4 sqrt(2))=log 2 (256 sqrt(2)=log 2(361.984)<BR>\n" );
document.write( "2^8.5-362.04<BR>\n" );
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