document.write( "Question 1090477: AOB is a straight line. OD bisect angle AOC. If angle AOC is 12 less than three times angle BOC, find angle COD. \n" ); document.write( "

Algebra.Com's Answer #704946 by KMST(5328) $\"\"$ $\"About$

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If it is something like this (or its mirror image,
\n" ); document.write( "with A on the left end)
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\n" ); document.write( "The phrase \"12 less than...\" tells me that it is $\"12%5Eo\"$ ,
\n" ); document.write( "and that angles are supposed to be measured in degrees
\n" ); document.write( "Let it be $\"x=BOC\"$ .
\n" ); document.write( "Then, $\"AOC=3x-12\"$ , and
\n" ); document.write( " $\"AOC%2BBOC=AOB\"$
\n" ); document.write( "translates into $\"AOC%2Bx=180\"$ and
\n" ); document.write( " $\"3x-12%2Bx=180\"$
\n" ); document.write( "Simplifying and solving:
\n" ); document.write( " $\"4x-12=180\"$
\n" ); document.write( " $\"4x=180%2B12\"$
\n" ); document.write( " $\"4x=192\"$
\n" ); document.write( " $\"x=192%2F4\"$
\n" ); document.write( " $\"x=48\"$
\n" ); document.write( " $\"AOC=180-48=132\"$
\n" ); document.write( "Then $\"AOD=COD=AOC%2F2=132%2F2=highlight%2866%29\"$
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