document.write( "Question 1090347: Fig. 4 shows a cone. The angle between the axis and the slant edge is 30°. Water is poured into the
\n" ); document.write( "cone at a constant rate of 2 cm3 per second. At time t seconds, the radius of the water surface is r cm and the volume of water in the cone is V cm3.\r
\n" ); document.write( "\n" ); document.write( "Show that V= (sqrt3/3*pi*r^3) and find dv/dr
\n" ); document.write( "[You may assume that the volume of a cone of height h and radius r is (1/3*pi*r^2*h)]\r
\n" ); document.write( "\n" ); document.write( "I worked it out but could only prove that V= sqrt3/3*pi*r^2... why would h equal (sqrt 3 r) and not just sqrt 3?\r
\n" ); document.write( "\n" ); document.write( "Thank you ever so much!!! \r
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Algebra.Com's Answer #704939 by Fombitz(32388)\"\" \"About 
You can put this solution on YOUR website!
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\n" ); document.write( "\"h=r%2A%28sqrt%283%29%2F3%29\"
\n" ); document.write( "So then,
\n" ); document.write( "\"V=%28pi%2F3%29r%5E2%2Ah\"
\n" ); document.write( "\"V=%28pi%2F3%29r%5E2%2Ar%28sqrt%283%29%2F3%29\"
\n" ); document.write( "\"V=%28%28sqrt%283%29pi%29%2F9%29r%5E3\"
\n" ); document.write( "So then differentiating,
\n" ); document.write( "\"dV%2Fdr=%28%28sqrt%283%29pi%29%2F9%293r%5E2\"
\n" ); document.write( "\"dV%2Fdr=%28%28sqrt%283%29pi%29%2F3%29r%5E2\"
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