document.write( "Question 1090481: P, Q, R, S and T are on line k such that Q is the midpoint of PT, R is the midpoint of QT, and S is the midpoint of RT. If PS = 9, then ehat is PT? \n" ); document.write( "
Algebra.Com's Answer #704927 by jim_thompson5910(35256)![]() ![]() ![]() You can put this solution on YOUR website! \n" ); document.write( "Step 1) Draw out a horizontal line and label it k. \n" ); document.write( "--------------------- \n" ); document.write( "Step 2) Plot the points P, Q, R, S, T (in that order from left to right) on the line k \n" ); document.write( "This is what you should have so far \n" ); document.write( " ![]() \n" ); document.write( "--------------------- \n" ); document.write( "Step 3) \n" ); document.write( "Since \"S is the midpoint of RT\", we know that RS = ST = x which is marked in purple for the figure below. \n" ); document.write( "Since \"R is the midpoint of QT\", we know that QR = RT = y which is marked in green for the figure below. \n" ); document.write( "Since \"Q is the midpoint of PT\", we know that PQ = QT = z which is marked in red for the figure below. \n" ); document.write( " ![]() \n" ); document.write( "x, y and z are unknown for now \n" ); document.write( "--------------------- \n" ); document.write( "Step 4) \n" ); document.write( "Note how two copies of x can be combined to form y. On one hand, RS+ST = RT and at the same time x+x = 2x = y (in step 3 we have RS = ST = x; RT = y). This means y = 2x. \n" ); document.write( "Put another way: \n" ); document.write( "RT = RS + ST \n" ); document.write( "RT = x + x \n" ); document.write( "RT = 2x \n" ); document.write( "RT = y \n" ); document.write( "So y = 2x \n" ); document.write( "--------------------- \n" ); document.write( "Step 5) \n" ); document.write( "Using similar logic used in step 4, we can say that z = 2y. This is because z = QT and QT = QR+RT = y+y = 2y. By the transitive property, if z = QT and QT = 2y, then z = 2y. \n" ); document.write( "--------------------- \n" ); document.write( "Step 6) \n" ); document.write( "Refer to the figure in step 3 to determine that \n" ); document.write( "PQ = z \n" ); document.write( "QR = y \n" ); document.write( "RS = x \n" ); document.write( "Note how PQ+QR+RS = PS by the segment addition postulate. \n" ); document.write( "So, \n" ); document.write( "PS = PQ+QR+RS \n" ); document.write( "PS = z+y+x \n" ); document.write( "PS = 2y+y+x ... z has been replaced with 2y (see step 5) \n" ); document.write( "PS = 2(2x)+2x+x ... every y has been replaced with 2x (see step 4) \n" ); document.write( "PS = 4x+2x+x \n" ); document.write( "PS = 7x \n" ); document.write( "--------------------- \n" ); document.write( "Step 7) \n" ); document.write( "Back in the previous step, we found out that PS = 7x. We are given that PS = 9. Use the substitution property to say \n" ); document.write( "PS = 9 \n" ); document.write( "7x = 9 \n" ); document.write( "7x/7 = 9/7 \n" ); document.write( "x = 9/7 \n" ); document.write( "--------------------- \n" ); document.write( "Step 8) \n" ); document.write( "Now we can find the length of PT \n" ); document.write( "PT = PQ + QT \n" ); document.write( "PT = z + z \n" ); document.write( "PT = 2*z \n" ); document.write( "PT = 2*(2y) ... z has been replaced with 2y (see step 5) \n" ); document.write( "PT = 4*y \n" ); document.write( "PT = 4*(2x) ... y has been replaced with 2x (see step 4) \n" ); document.write( "PT = 8*x \n" ); document.write( "PT = 8*(9/7) ... x has been replaced wth 9/7 (see step 7) \n" ); document.write( "PT = 72/7 \n" ); document.write( "PT = 10.2857142857142 \n" ); document.write( "The decimal value is approximate. You can use long division or a calculator to come up with that result. \n" ); document.write( "--------------------------------------------------------------- \n" ); document.write( "--------------------------------------------------------------- \n" ); document.write( "Answer as a fraction: 72/7 \n" ); document.write( "Answer in decimal form: 10.2857142857142 (round this however you need to) \n" ); document.write( " \n" ); document.write( " |