document.write( "Question 1090443: The variable w varies jointly with y and the square of x and inversely with the square root of z.
\n" ); document.write( "Also w=-3 when x= 2sqrt3, y=-1 and z=1/4. Suppose that w=1/2x, y=2x and z=8y. Find x.
\n" ); document.write( "please help
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Algebra.Com's Answer #704880 by Boreal(15235)\"\" \"About 
You can put this solution on YOUR website!
w=k*yx^2/sqrt(z)
\n" ); document.write( "now substitute
\n" ); document.write( "-3=k*-1*(2 sqrt(3)^2)/sqrt(1/4)=k * -1*12/(1/2)=k*-24
\n" ); document.write( "k=1/8
\n" ); document.write( "now use k in the problem with a different missing variable.
\n" ); document.write( "w=k*yx^2/sqrt(z)
\n" ); document.write( "(1/2)x=(1/8)*2x*x^2/sqrt(16x); note, I am setting w=(1/2)x not (1/2x)
\n" ); document.write( "(1/2)x=2x^3/[8 *4 sqrt(x)]
\n" ); document.write( "multiply by 2
\n" ); document.write( "x=4x^3/(8*4 sqrt(x))
\n" ); document.write( "32x^(3/2)=4x^3
\n" ); document.write( "8=x^(3/2)
\n" ); document.write( "raise everything to the (2/3) power
\n" ); document.write( "8^2/3)=4=x ANSWER
\n" ); document.write( "x=4; therefore w=2,y=8 and z=64. See if this works
\n" ); document.write( "2=(1/8)*8*16/sqrt(64).
\n" ); document.write( "This is 2=16/8, which is true.\r
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