document.write( "Question 96870This question is from textbook
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\n" ); document.write( "y=[-3x+5]
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Algebra.Com's Answer #70487 by jim_thompson5910(35256)\"\" \"About 
You can put this solution on YOUR website!
\"y=abs%28-3x%2B5%29\" Start with the given equation\r
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\n" ); document.write( "\n" ); document.write( "Break up the absolute value equation into two parts. Remember \"abs%28x%29=a\" becomes \"x=a\" or \"x=-a\"\r
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\n" ); document.write( "\n" ); document.write( "\"-y=-3x%2B5\" or \"y=-3x%2B5\" \r
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\n" ); document.write( "\n" ); document.write( "\"-1%28-y%29=-1%28-3x%2B5%29\"For the first equation, multiply both sides by -1 to make y positive\r
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\n" ); document.write( "\n" ); document.write( "\"y=3x-5\" Distribute\r
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\n" ); document.write( "\n" ); document.write( "So we now have these two equations\r
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\n" ); document.write( "\n" ); document.write( "\"y=3x-5\" or \"y=-3x%2B5\" \r
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\n" ); document.write( "\n" ); document.write( "Now graph the two equations\r
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\n" ); document.write( "\n" ); document.write( "\"+graph%28+500%2C+500%2C+-10%2C+10%2C+-10%2C+10%2C+3x-5%2C+-3x%2B5%29+\" Graph of \"y=3x-5\" (red) and \"y=-3x%2B5\"(green)\r
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\n" ); document.write( "\n" ); document.write( "Remember, an absolute value graph is in a \"V\" shape, so that means the graph \"y=-3x%2B5\" is the left branch and \"y=3x-5\" is the right branch. \r
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\n" ); document.write( "\n" ); document.write( "So just erase the portions of the graph below the intersection like this\r
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\n" ); document.write( "\n" ); document.write( "\"+graph%28+500%2C+500%2C+-10%2C+10%2C+-10%2C+10%2C+abs%28-3x%2B5%29%29+\" Graph of \"y=abs%28-3x%2B5%29\"
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