document.write( "Question 1090355: If sinx + cosx = 3/4 find sinx - cosx \n" ); document.write( "
Algebra.Com's Answer #704786 by Alan3354(69443)![]() ![]() You can put this solution on YOUR website! If sinx + cosx = 3/4 \n" ); document.write( "sin^2 + 2sin*cos + cos^2 = 9/16 \n" ); document.write( "1 + sin(2x) = 9/16 \n" ); document.write( "sin(2x) = -7/16 \n" ); document.write( "==============\r \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "find sinx - cosx \n" ); document.write( "(sin - cos)^2 = sin^2 - sin(2x) + cos^2 = 1 - sin(2x) \n" ); document.write( "= 1 - (-7/16) = 23/16 \n" ); document.write( "sin - cos = sqrt(23)/4 \n" ); document.write( "or -sqrt(23)/4 \n" ); document.write( "===================== \n" ); document.write( "Clever? \n" ); document.write( " |