document.write( "Question 1090324: Approximate, to the nearest 10l, the solutions of the equation that are in
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document.write( "[0c, 360c).
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document.write( "tantheta = 2.798\r
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document.write( "I don't knoq what to do. Please help! \n" );
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Algebra.Com's Answer #704775 by Theo(13342) You can put this solution on YOUR website! you're looking at tangent of theta = 2.798.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "find the arc tangent of 2.798 and it will tell you that the angle whose tangent is 2.798 is equal to 70.3332048 degrees.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "that would be the angle in the first quadrant of the unit circle.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "the tangent is positive in the first quadrant and the third quadrant.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "the angle in the third quadrant that is equivalent to 70.3332048 degrees in the first quadrant is equal to 180 + 70.3332048 which is equal to 250.3332048 degrees.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "your two solutions are 70.3332048 degrees and 250.3332048 degrees.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "if you drew a graph of the tangent function, it would look like this:\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( " \r\n" ); document.write( " \n" ); document.write( "\n" ); document.write( "these angles are equivalent because the value of their tangent function is the same.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "tangent of 70.3332048 degrees is equal to 2.798\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "tangent of 250.3332048 degrees is equal to 2.798\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "if you looked at the angle whose tangent is 2.798 on the unit circle, it would look like this in the first quadrant.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( " \r\n" ); document.write( " \n" ); document.write( "\n" ); document.write( "the tangent in the first quadrant is positive because the sine and the cosine are positive.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "it would look like this in this in the third quadrant.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( " \r\n" ); document.write( " \n" ); document.write( "\n" ); document.write( "the reference angle is the same as the angle in the first quadrant.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "it would look like this:\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( " \r\n" ); document.write( " \n" ); document.write( "\n" ); document.write( "the tangent in the third quadrant is positive because the sine and the cosine are negative.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "tangent = sine / cosine\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "positive / positive = positive (first quadrant)\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "negative / negative = positive (third quadrant)\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "here's a reference on the unit circle.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "http://www.montereyinstitute.org/courses/DevelopmentalMath/COURSE_TEXT2_RESOURCE/U19_L1_T3_text_final.html\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "if you ave any questions about this, let me know and i'll answer as best i can.\r \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " |