document.write( "Question 1090312: A line is graphed in the xy-plane. If the line has a positive slope and a negative y-intercept, why (-3,3) cannot lie on the line? \n" ); document.write( "

Algebra.Com's Answer #704774 by ikleyn(52847) $\"\"$ $\"About$

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document.write( "If the line has a negative y-intercept, it implies that the corresponding linear function is negative at x = 0.\r\n" );
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document.write( "If, in addition, the line has positive slope, it means that the values of the corresponding linear function \r\n" );
document.write( "are even lesser in the negative domain of x.\r\n" );
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document.write( "Meanwhile, the point (-3,3) has negative component x= -3, but positive y= 3.\r\n" );
document.write( "CONTRADICTION.\r\n" );
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