document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1090305>Question 1090305</A>: <I><SPAN STYLE=\"word-break: break-all;\"> use the p over q method and synthetic division to factor the polynomial P(x). then solve P(x)=0\r<BR>\n" );
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document.write( "P(x)=x^3+4x^2+x-6 </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #704733 by </B><A HREF=/tutors/aboutme.mpl?userid=Boreal><B>Boreal(15235)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=Boreal><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=Boreal><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=704733\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> P(x)=x^3+4x^2+x-6<BR>\n" );
document.write( "p is 6 and q is 1, the coefficient of x^3<BR>\n" );
document.write( "therefore the possible integer roots are +/-1,2,3,6<BR>\n" );
document.write( "synthetic division with <BR>\n" );
document.write( "1/1----4----1---minus 6<BR>\n" );
document.write( "==1==5----6----0<BR>\n" );
document.write( "1 is a root, so (x-1) is a factor<BR>\n" );
document.write( "the other factor may be read off the division as x^2+5x+6, which is (x+3)(x+2)<BR>\n" );
document.write( "Those are the three factors, and roots are -3, -2, and 1<BR>\n" );
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document.write( " </SPAN>\n" );
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