document.write( "Question 1090285: Help please \r
\n" ); document.write( "\n" ); document.write( "Find the slant asymptote,the vertical asymptote,the x and the y intercepts and then sketch the graph of
\n" ); document.write( "f(x)=(x^3+x^2)/x^2-4
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Algebra.Com's Answer #704730 by MathLover1(20850)\"\" \"About 
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\"f%28x%29=%28x%5E3%2Bx%5E2%29%2F%28x%5E2-4%29\" -> form \"f%28x%29+=+p%28x%29+%2F+q%28x%29\"\r
\n" ); document.write( "\n" ); document.write( "you are given a rational function written as the ratio of two polynomials where the denominator \"q%28x%29\" isn't zero\r
\n" ); document.write( "\n" ); document.write( "Vertical Asymptotes:
\n" ); document.write( "An asymptote is a line that the curve approaches but does not cross. The equations of the vertical asymptotes can be found by finding the roots of \"q%28x%29\". Completely ignore the numerator when looking for vertical asymptotes, \"only\" the \"denominator\"\"+matters\". \r
\n" ); document.write( "\n" ); document.write( "\"x%5E2-4=0\"\r
\n" ); document.write( "\n" ); document.write( "\"x%5E2=4\"\r
\n" ); document.write( "\n" ); document.write( "\"x=sqrt%284%29\"\r
\n" ); document.write( "\n" ); document.write( "\"x=+2\" or \"x=-2\"\r
\n" ); document.write( "\n" ); document.write( "so, vertical asymptotes: \"x=+2\" and \"x=-2\"\r
\n" ); document.write( "\n" ); document.write( "Horizontal Asymptotes:\r
\n" ); document.write( "\n" ); document.write( "The location of the horizontal asymptote is determined by looking at the degrees of the numerator (\"n\") and denominator (\"m\").\r
\n" ); document.write( "\n" ); document.write( " If \"n%3Cm\", the x-axis, \"y=0\" is the \"horizontal\" asymptote.
\n" ); document.write( " If \"n=m\", then \"y=an+%2F+bm\" is the \"horizontal\" asymptote. That is, the ratio of the leading coefficients.
\n" ); document.write( " If \"n%3Em\", there is \"no\" horizontal asymptote.
\n" ); document.write( "However, if \"n=m%2B1\", there is an \"oblique\" or \"slant\" asymptote.\r
\n" ); document.write( "\n" ); document.write( "in your case,\"n=3\" and \"m=2\"; so, \"n%3Em\" which means there is \"no\" horizontal asymptote\r
\n" ); document.write( "\n" ); document.write( "Oblique Asymptotes:\r
\n" ); document.write( "\n" ); document.write( "When the degree of the numerator is exactly one more than the degree of the denominator, the graph of the rational function will have an oblique (slant) asymptote. \r
\n" ); document.write( "\n" ); document.write( "in your case \"n=3\" and \"m=2\" and \"n=m%2B1\"; so, you have a slant asymptote
\n" ); document.write( "To find the equation of the oblique asymptote, perform long division (synthetic if it will work) by dividing the denominator into the numerator.\r
\n" ); document.write( "\n" ); document.write( "\"f%28x%29=%28x%5E3%2Bx%5E2%29%2F%28x%5E2-4%29\"\r
\n" ); document.write( "\n" ); document.write( "------------\"highlight%28x%2B1%29\"
\n" ); document.write( "\"+%28x%5E2-4%29\"/\"x%5E3%2Bx%5E2\"
\n" ); document.write( "-------------\"x%5E3-4x\"
\n" ); document.write( "----------------\"0%2Bx%5E2\"
\n" ); document.write( "-----------------\"x%5E2-4\"
\n" ); document.write( "---------------------\"4\"\r
\n" ); document.write( "\n" ); document.write( "so, \"f%28x%29=%28x%5E3%2Bx%5E2%29%2F%28x%5E2-4%29\" is asymptotic to \"f%28x%29=highlight%28x+%2B+1%29\"\r
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